poojaaa1
poojaaa1
31-03-2018
Mathematics
contestada
Can somebody help me????
Respuesta :
WojtekR
WojtekR
31-03-2018
[tex]f(x)=5x^2-3\\\\\\ f(x+a)=5(x+a)^2-3=5(x^2+2ax+a^2)-3=\\\\=\boxed{5x^2+10ax+5a^2-3}[/tex]
On the other hand:
[tex]f(x+a)=5x^2+30x+42[/tex]
so:
[tex]10ax=30x\\\\10a=30\qquad|:10\\\\\boxed{a=3}[/tex]
Answer C.
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