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PLZ HELPP MEE DUE TONIGHT!!!!!!!!!!!!!

The equation x^2+px−35=0 has one root that is equal to 7. Find the other root and the value of the coefficient p.


x^2= x squared

Respuesta :

calculista
we know that
x²+px−35=0-------> has one root that is equal to 7
so
substitute x=7 in the equation
7²+p*7−35=0
49+p*7−35=0
14+p*7=0
p=-14/7------> p=-2

the answer Part a) is 
the value of the coefficient p is -2

Part b) Find the other root
x²+px−35=0-----> x²-2x−35=0

using a graph tool-------> to resolve the second order equation
see the attached figure

the other root is
x=-5

the answer part b) is
 the value of  the other root is -5
Ver imagen calculista

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