Answer:
Step-by-step explanation:
The given equation is:
[tex]f(x)=x^2+12x+32[/tex]
Simplifying the above expression, we have
[tex]f(x)=x^2+4x+8x+32[/tex]
[tex]f(x)=x(x+4)+8(x+4)[/tex]
[tex]f(x)=(x+4)(x+8)[/tex]
Thus, zeroes of the given function will be:
[tex]f(x)=0[/tex]
[tex](x+4)(x+8)=0[/tex]
[tex]x=-4 and x=-8[/tex]
Therefore the zeroes of the given function are [tex]x=-4 and x=-8[/tex].
