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An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? You may use a trigonometry table

Respuesta :

The height difference is found by
[tex]\delta H=400sin(5 \°)=34.86m[/tex]
Then the change in potential energy is
[tex]E=mgh=(80.0kg)(9.8 \frac{kgm}{s^2})(34.86)= 27332J[/tex]

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