Question a chemist mixes 35 milliliters of a solution that is 18% acid with 90 milliliters of a solution that is 68% acid. answer the questions below. do not do any rounding.
Missing questions: a) How many milliliters of acid are in the resulting mixture? b) What percentage of the resulting mixture is acid? a) V₁ = 35 ml. ω₁ = 18% = 0,18. V₂ = 90 ml. ω₂ = 68% = 0,68. V(acid) = V₁ · ω₁ + V₂ · ω₂. V(acid) = 35 ml · 0,18 + 90 ml · 0,68 = 67,5ml. b) ω(acid) = 67,5 ml ÷ (35 ml + 90 ml). ω(acid) = 54%.