A right triangle with an area of x2 – 4 square units has a leg that measures 2x + 4 units. determine the length of the other leg of the triangle.

Respuesta :

A= leg1*leg2/2 so  x^2-4=(2x+4)*leg2/2=(x+2)*leg2

leg2=x^2-4/x+2=(x+2)(x-2)/x+2=x-2

the answer is x-2