Respuesta :

Hosein

[tex] \sin(2x) = \cos(x) \\ 2 \sin(x) \cos(x) = \cos(x) \\ \cos(x) (2 \sin(x) - 1) = 0[/tex]
so
[tex] \cos(x) = 0 > > > x = \frac{\pi}{2} + k\pi \\ \sin(x) = \frac{1}{2} > > > x = \frac{\pi}{6} + 2k\pi \\ or \: x = \frac{5\pi}{6} + 2k\pi[/tex]
[tex]x = \frac{\pi}{2} or \frac{3\pi}{2} \\ x = \frac{\pi}{6} or \frac{5\pi}{6} [/tex]

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