zhada
zhada
30-07-2017
Mathematics
contestada
Can someone please help me solve 91
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konrad509
konrad509
30-07-2017
[tex]3x^3+7x^2-20x=0\\ x(3x^2+7x-20)=0\\ x(3x^2-5x+12x-20)=0\\ x(x(3x-5)+4(3x-5))=0\\ x(x+4)(3x-5)=0\\ x=0 \vee x=-4 \vee x=\dfrac{5}{3}[/tex]
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irspow
irspow
30-07-2017
3x^3+7x^2-20x=0 factor out x first
x(3x^2+7x-20)=0
x(3x^2+12x-5x-20)=0
x(3x(x+4)-5(x+4))=0
x(3x-5)(x+4)=0
x={-4, 0, 5/3}
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