bluetigerbird2823 bluetigerbird2823

30-07-2017
Mathematics

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The difference between the squares of two numbers is 7. four times the square of the first number increased by the square of the second number is 73. find the numbers.

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30-07-2017

let a = x^2 and b=y^2
a-b=7
4a+b=73
4(7+b)+b=73 5b=45 b=9
a=7+b = 7+9 = 16
Then
x^2=16, x=+-4
y^2=9, y=+-3

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