Respuesta :
5H₂SO₄ + 8NaI = 4I₂ + 4H₂O + H₂S + 4Na₂SO₄
S⁺⁶ + 8e⁻ = S⁻² f=8
2I⁻ - 2e⁻ = I₂
M(H₂SO₄)=98 g/mol
M(eqi)=98/8=12.25 g/mol
S⁺⁶ + 8e⁻ = S⁻² f=8
2I⁻ - 2e⁻ = I₂
M(H₂SO₄)=98 g/mol
M(eqi)=98/8=12.25 g/mol