Given:
Sample Mean = 30
Sample size = 1000
Population Standard deviation or σ=2
Confidence interval = 95%
to compute for the confidence interval
Population Mean or μ= sample mean ± (z×SE)
where:
SE→ Standard Error
SE=σ√n= 30√1000=0.9486
Critical Value of z for 95% confidence interval =1.96
μ=30±(1.96×0.9486)
μ=30±1.8594
Upper Limit
μ = 30 + 1.8594 = 31.8594
Lower Limit
μ = 30 − 1.8594 = 28.1406
answer: 28.1406<u<31.8594
