Seudónimo Seudónimo
  • 29-05-2017
  • Mathematics
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I need help with 26!!

I need help with 26 class=

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MarcosRener MarcosRener
  • 29-05-2017
tan 45°= 15/x
x= 15/tan 45°
x= 15

y=[tex] \sqrt{15^2+15^2} =15 \sqrt{2} [/tex]
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