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28-05-2017
Mathematics

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3sec^X+8=10sec^X then find the value of tanx

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LammettHash LammettHash

02-06-2017

Presumably, "sec^X" is supposed to say [tex]\sec^2x[/tex].

[tex]3\sec^2x+8=10\sec^2x\iff7\sec^2x-8=7(\sec^2x-1)-1=7\tan^2x-1=0[/tex]
[tex]\implies\tan^2x=\dfrac17[/tex]
[tex]\implies\tan x=\pm\dfrac1{\sqrt7}[/tex]

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