The area of a rectangular garden is given by the trinomial x^2+6x-27. what are the possible dimensions of the rectangle? use factoring

Question

contestada

Respuesta :

Аноним Аноним · Answer 1 · 2017-03-29T20:18:46+02:00

A = x^2 + 6x - 27 A = x^2 + 9x - 3x - 27 A = x(x+9)-3(x+9) A = (x+9)(x-3) A = lw l = (x+9) w =(x-3)

Answer Link

AlonsoDehner AlonsoDehner · Answer 2 · 2019-03-09T04:08:39+01:00

Answer:

Step-by-step explanation:

Given that a garden is in rectangular form

Area of the garden = [tex]x^2+6x-27[/tex]

We know that area of a rectangle = length x width

Hence length x width = [tex]x^2+6x-27[/tex]

There can be infinite number of answers for this equation.

Let us assume that both length and width are rational.

Then the factors would be answers.

Factorise

[tex]x^2+6x-27[/tex] as

[tex](x+9)(x-3)[/tex]

Since normally length would be longer, we can say

length = x+9 and width = x-3, for x >3.