To determine the distance travel by the car in this motion we can use the formula:
[tex]x-x_0=v_0t+\frac{1}{2}at^2_{}[/tex]if we assume that the car starts at the origin and that the initial velocity is zero.
In this case we have that x0=0, v0=0, a=2.6 and t=14, then:
[tex]\begin{gathered} x-0=(0)t+\frac{1}{2}(2.6)(14)^2 \\ x=254.8 \end{gathered}[/tex]Therefore the car travels 254.8 meters.
