Respuesta :

[tex]\begin{gathered} f(x)=x^2+2x-4 \\ (a)f(0)=0+0-4 \\ =-4 \\ g(-4)=\frac{1}{-4+1} \\ =\frac{1}{-3} \\ \\ (b)g(-2)=\frac{1}{-2+1} \\ =\frac{1}{-1} \\ =-1 \\ f(-1)=(-1)^2+2(-1)-4 \\ =1-2-4 \\ =-5 \end{gathered}[/tex]

Otras preguntas