Answer:
x=2
y=3
Explanation:
Given the system of equations:
[tex]\begin{gathered} x+4y=14 \\ x+3y=11 \end{gathered}[/tex]Subtract to eliminate x:
[tex]\begin{gathered} (x-x)+(4y-3y)=14-11 \\ 0+y=3 \\ y=3 \end{gathered}[/tex]Next, substitute y=3 to solve for x:
[tex]\begin{gathered} x+4y=14 \\ x+4(3)=14 \\ x+12=14 \\ x=14-12 \\ x=2 \end{gathered}[/tex]The solution to the system is x=2, y=3.
