AayushaA701889 AayushaA701889
  • 31-10-2022
  • Mathematics
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y varies directly as xy equals 5 when X is 8 how do you find y when X is 9

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AmillianaA677178 AmillianaA677178
  • 31-10-2022

Given, y varies directly as x

So,

[tex]y=c\cdot x[/tex]

Where c is a constant

When y equals 5 when x is 8

So,

[tex]\begin{gathered} 5=c\cdot8 \\ c=\frac{5}{8} \\ \end{gathered}[/tex]

So, the relation between y and x

[tex]y=\frac{5}{8}x[/tex]

now , when x = 9

Substitute with x to find y

[tex]y=\frac{5}{8}\cdot9=\frac{45}{8}[/tex]

So, the answer is option 2. y = 45/8

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