Given,
[tex]\lvert3x+2\rvert-2>3[/tex]
Now, solving the above equation ,
[tex]\begin{gathered} \lvert3x+2\rvert-2>3 \\ \pm(3x-2)-2>3 \\ 3x-2-2>3 \\ 3x>3+4 \\ 3x>7 \\ x>2.3 \\ -(3x-2)-2>3 \\ -3x+2-2>3 \\ -3x>3 \\ -x>1 \\ x<-1 \end{gathered}[/tex]
So, the solution is,
[tex]\begin{gathered} 2.31} \end{gathered}[/tex]
So, the correct option is option B.
