Respuesta :

Given data

*The half lifetime of potassium-hild is T = 5.63 years

*The given amount is N = 200.0 g

*The given time is t = 36 year

The expression for the radioactivity decay is given as

[tex]N=N_0(\frac{1}{2})^{\frac{t}{T}}[/tex]

Substitute the values in the above expression as

[tex]\begin{gathered} N=200(\frac{1}{2})^{\frac{36}{5.63}} \\ N_{}=2.63\text{ g} \end{gathered}[/tex]