AhsokaH430730 AhsokaH430730
  • 30-10-2022
  • Physics
contestada

So I got stuck on this question

Respuesta :

HarukaY184144 HarukaY184144
  • 30-10-2022
[tex]\begin{gathered} d=v0\cdot t+\frac{at^2}{2} \\ d=0\cdot1.6+\frac{9.81\cdot1.6^2}{2} \\ d=12.557m \\ \end{gathered}[/tex]

The initial speed is 0, then while he falls down the speed increase

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