Respuesta :

[tex]\begin{gathered} 9x-y=32 \\ x+9y=40 \\ \text{ using elimination method} \\ \text{ multiply equation 1 by 9} \\ 81x-9y=288 \\ x+9y=40 \\ \text{add both equations} \\ 82x=328 \\ x=\frac{328}{82} \\ x=4 \\ \text{substitute x in any of the equations} \\ 4+9y=40 \\ 9y=40-4 \\ y=\frac{36}{9} \\ y=4 \end{gathered}[/tex]

Otras preguntas