Respuesta :

The given equation is

[tex]12-x^2=0[/tex]

Let's solve for x.

[tex]\begin{gathered} 12=x^2 \\ x=\pm\sqrt[]{12} \\ x=\pm\sqrt[]{4\cdot3} \\ x=\pm2\sqrt[]{3} \end{gathered}[/tex]

Hence, the correct answer is the first answer choice.

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