Factors are (6x-5) and (7x+1).
Given:
The quadratic equation is
[tex]42x^2=29x+5[/tex]
The objective is to factor the equation.
The quadratic equation can be written as,
[tex]\begin{gathered} 42x^2=29x+5 \\ 42x^2-29x-5=0 \end{gathered}[/tex]
On factorizing the above equation,
[tex]\begin{gathered} 42x^2+6x-35x-5=0 \\ 6x(7x+1)-5(7x+1)=0 \\ (6x-5)(7x+1)=0 \end{gathered}[/tex]
Hence, the factors are (6x-5)(7x+1)=0.
