FaithlynH585687 FaithlynH585687

30-10-2022
Mathematics

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16х2 +10x - 27 - бх +5What are the solutions to this equation? (the 16x2, the two is squared)

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GavanJ306010 GavanJ306010

30-10-2022

16х² +10x - 27 - бх +5 = 0

16х² + (10x - 6x) + (-27 + 5) = 0 combinig similar terms

16х² + 4x - 22 = 0

Using quadratic formula,

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