start by solving the other leg
[tex]\begin{gathered} 2x-5=67 \\ 2x=67+5 \\ 2x=72 \\ x=36 \end{gathered}[/tex]draw the triangle
Use the pythagorean theorem to find the hypotenuse
[tex]\begin{gathered} c^2=a^2+b^2 \\ c=\sqrt[]{a^2+b^2} \\ c=\sqrt[]{(27)^2+(36)^2} \\ c=\sqrt[]{2025} \\ c=45 \end{gathered}[/tex]
