Solution:
Given the equation;
[tex]2x^2+8x+4=0[/tex]
Its solution is;
[tex]x=\frac{-8\pm\sqrt{32}}{4}[/tex]
Now, we would simplify this as;
[tex]\begin{gathered} x=\frac{-8\pm4\sqrt{2}}{4} \\ \\ x=\frac{4(-2\pm\sqrt{2})}{4} \\ \\ x=-2\pm\sqrt{2} \end{gathered}[/tex]
CORRECT OPTION: C
