SOLUTION
The figure ABCD is a parallelogram
We have also gotten a 50 degree angle on the ray, using angles on a straightline = 180 degrees,
180 - 130 = 50 degrees
We labelled angle ADE as x.
ADE is a triagle. Sum of angles in a triangle = 180 degrees
So, 110 + 50 + x = 180
160 + x = 180
x = 180 - 60
x = 20 degrees.
Therefore, angle ADE = 20 degrees
