SOLUTION
The perimeter of the rectangle is given as 302.
It is given that the width is 68.
Recal the formula for perimeter of a rectagle:
[tex]P=2(l+w)[/tex]Substituting values gives:
[tex]302=2(l+68)[/tex]Solve the equation for l.
[tex]\begin{gathered} \frac{302}{2}=l+68 \\ 151=l+68 \\ l=151-68 \\ l=83 \end{gathered}[/tex]Therefore the length of the rectangle is 83
