x^2e^x-3xe^x+2e^x=0
Factorize the e^x
e^x ( x^2 - 3x + 2 ) = 0
Factorize the trionomial x^2 - 3x + 2
e^x ( x - 2) (x - 1) =0
Then use the zero factor theorem if e^x ( x - 2) (x - 1) =0, then ( x - 2) =0 or (x - 1) =0
Solve for x
( x - 2) =0
x = 2
(x - 1) = 0
x = 1
So the solution is x = 2 and x = 1
