equation of line
y=mx+b
If m=-3/2
we have
[tex]\begin{gathered} y=mx+b \\ y=-\frac{3}{2}\cdot x+b \end{gathered}[/tex]From points (2,3), we find b
[tex]\begin{gathered} y=-\frac{3}{2}\cdot x+b \\ 3=-\frac{3}{2}\cdot2+b \\ 3=-3+b \\ b=6 \end{gathered}[/tex]Therefore
[tex]y=-\frac{3}{2}\cdot x+6[/tex]