KalyF472672 KalyF472672
  • 30-10-2022
  • Mathematics
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2y+12 greater than or equal to 42

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MayzieU762322 MayzieU762322
  • 30-10-2022
[tex]\begin{gathered} 2y+12\ge42 \\ 2y\ge42-12 \\ 2y\ge30 \\ y\ge\frac{30}{2} \\ y\ge15 \end{gathered}[/tex]

Then, the solution of the inequality is:

[tex]y\ge15[/tex]

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