Respuesta :

We will solve a follows:

[tex]\log _2(512)=x\Rightarrow x=9[/tex]

***Explanation of the procedure using change of base for a logarithm***

[tex]\log _a(n)=\frac{\log _b(n)}{\log _b(a)}[/tex]

So:

[tex]\log _2(512)=\frac{\log(512)}{\log(2)}=9[/tex]

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