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Suppose that you are driving off in your car starting from rest and youaccelerate at a constant acceleration of 3.5 m/s^2. How far would you havetraveled after 20s?

Respuesta :

Answer: The distance traveled by the car is 700m

Explanation:

From the information given,

acceleration, a = 3.5m/s^2

initial velocity, u = 0 because the car started from rest

time, t = 20 s

We want to find distance traveled, s

We would apply the Newton's formula of motion below

s = ut + 1/2at^2

By substituting the given values into the formula,

s = 0 x 20 + 1/2 x 3.5 x 20^2

s = 0 + 700

s = 700

The distance traveled by the car is 700m

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