Given
[tex]\frac{9x^2y}{z}\div\frac{3x}{2x^2z}[/tex]To simplify.
Explanation:
It is given that,
[tex]\frac{9x^2y}{z}\div\frac{3x}{2x^2z}[/tex]That implies,
[tex]\begin{gathered} \frac{9x^2y}{z}\div\frac{3x}{2x^2z}=\frac{9x^2y}{z}\times\frac{2x^2z}{3x} \\ =\frac{18x^4yz}{3xz} \\ =6x^3y \end{gathered}[/tex]Hence, the answer is 6x³y.
