Answer:
2.82 A
Explanation:
The current of the wire can be calculated as:
[tex]I=\frac{Q}{t}[/tex]Where Q is the charge and t is the time.
The charge of an electron is 1.6 x 10^(-19) C, so the charge of 3.7 x 10^(18) electron is equal to
[tex]3.7\times10^{18}\text{ electrons}\times1.6\times10^{-19}\text{ C/electron}=0.592\text{ C}[/tex]Then, replacing Q = 0.592 C, and t = 0.21 s, we get:
[tex]I=\frac{0.592\text{ C}}{0.21\text{ s}}=2.82\text{ A}[/tex]Therefore, the answer is 2.82 A
