The radius of the cone is r=10 ft.
The slant height of the cone is l=22.4 ft.
The surface area of the cone is,
[tex]\begin{gathered} SA=\pi r(r+l) \\ =\pi\times10\times(10+22.4) \\ =1017.87\approx1017.9ft^2 \end{gathered}[/tex]Thus, the required surface area of the cone is 1017.9 square feet.
