Respuesta :

We will solve as follows:

[tex](\frac{240+55x}{x})/(\frac{270+35x}{x})=(\frac{240+55x}{x})\cdot(\frac{x}{270+35x})[/tex][tex]=\frac{240+55x}{270+35x}=\frac{11x+48}{7x+54}[/tex]

So, the solution is option A.