Respuesta :

[tex]\begin{gathered} \sqrt{90}-\sqrt{40}=\sqrt{9\times10}-\sqrt{4\times10} \\ \text{ =}\sqrt{9}\times\sqrt{10}-\sqrt{4}\times\sqrt{10} \\ \text{ =3}\sqrt{10}-2\sqrt{10} \end{gathered}[/tex]

taking √10 common,

[tex]\sqrt{10}(3-2)=\sqrt{10}[/tex]

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