Respuesta :

Let's solve the equation:

[tex]\begin{gathered} 22-\ln (5-x)=0 \\ \ln (5-x)=22 \\ e^{\ln (5-x)}=e^{22} \\ 5-x=e^{22} \\ x=5-e^{22} \\ x=-3.5849\times10^9 \end{gathered}[/tex]

Therefore the solution is:

[tex]x=-3.5849\times10^9[/tex]

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