calculatewe have the next equation of the parabola
[tex]y=-x^2+6x-5[/tex][tex]y=ax2+bx+c.[/tex]a=-1
b=6
c=-5
then we need to calculated the vertice using the next formula
coordinate x
[tex]x=\frac{-b}{2a}[/tex][tex]x=\frac{-6}{2(-1)}=\frac{-6}{-2}=3[/tex]for the coordinate y
y=-x^2 + 6x - 5=-(3)^2+6(3)-5=4
the coordinate of the vertice is (3,4)
