Given two similar triangles
[tex]\triangle ABC\sim\triangle RST[/tex]
so, the corresponding sides are proportional
[tex]\frac{AB}{RS}=\frac{BC}{ST}=\frac{AC}{RT}[/tex]
As shown in the figure:
AB = 4, AC = 6
RS = 2, RT = 3
so,
[tex]\begin{gathered} \frac{AB}{RS}=\frac{4}{2}=\frac{2}{1} \\ \\ \frac{AC}{RT}=\frac{6}{3}=\frac{2}{1} \end{gathered}[/tex]
The ratios can be written as:
[tex]undefined[/tex]
