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A driver turns the steering wheel clockwise to turn right. The forces, F, andF2, that the hands exert on the steering wheel form a couple. Given that themoment of couple about the center of steering wheel is 3 N m, both the F1and F2 are 5 N. Find the diameter of the steering wheel.

Respuesta :

The forces are,

[tex]F_1=F_2=5\text{ N}[/tex]

The distance between the forces is equal to the diameter of the wheel.

The moment is,

[tex]\begin{gathered} 3=F_1\times d \\ d=\frac{3}{5} \\ d=0.6\text{ m} \end{gathered}[/tex]

Hence, the diameter of the wheel is 0.6 m.

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