KhaleesiaE288298 KhaleesiaE288298
  • 29-10-2022
  • Mathematics
contestada

Hi, I am having some problems with this geometry question. We just learned tan, sin, and cosine. Can you help me?

Hi I am having some problems with this geometry question We just learned tan sin and cosine Can you help me class=

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RudraC20041 RudraC20041
  • 29-10-2022

The given triangle is

Recall that the formula for tan is

[tex]\tan \theta=\frac{Opposite\text{ side}}{\text{adjacent side}}[/tex][tex]\text{Substitute Opposite side=14 , adjacent side=x and }\theta=27^o,\text{ we get}[/tex]

[tex]\tan 27^o=\frac{14}{x}[/tex][tex]\text{Use }tan27^o=0.509.[/tex]

[tex]0.509=\frac{14}{x}[/tex]

[tex]x=\frac{14}{\text{0}.509}=27.505[/tex]

Hence the x value is 27.5.

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