where y is the second bucket, 8 is the rate of change and t the time on seconds
the buckets have the same amount when each one has 20oz, so we can replace y=20 and solve t to find the seconds to have the same amount on each bucket
[tex]\begin{gathered} 20=8t \\ t=\frac{20}{8} \\ t=2.5 \end{gathered}[/tex]so, the buckets would have the same amount of water when 2.5 seconds have passed
