Area for square with side length 2 inches:
A = base x height = 2 inches x 2 inches = 4 inches^2
Now, for a circle with a radius 1.2 inches, we have:
[tex]A=r^2\pi=(1.2)^2\text{ }\pi\text{ }\approx4.52in^2[/tex]
but notice that
[tex]4.52\text{ > 4}[/tex]
so we can conclude that the area of the square is less than the area of the given circle.
