hellofrom the question given, we have a triangle
let's use trigonometric ratio on this
SOHCAHTOA
[tex]\begin{gathered} \text{soh}=\sin \theta=\frac{opposite}{hypothenus} \\ \text{cah}=\cos \theta=\frac{adjacent}{hypothenus} \\ \text{toa}=\tan \theta=\frac{opposite}{adjacent} \end{gathered}[/tex]in this question, we have the value of an angle, and opposite but we are to solve for hypothenus.
the only ratio that would work for this is sine angle
[tex]\begin{gathered} \sin \theta=\frac{opp}{hyp} \\ \theta=38^0 \\ \text{opp}=1.3 \\ \text{hyp}=x \\ \sin 38=\frac{1.3}{x} \\ 0.6157=\frac{1.3}{x} \\ x=\frac{1.3}{0.6157} \\ x=2.1 \end{gathered}[/tex]from the calculations above, the value of x is equals to 2.1
