Given
[tex]\begin{gathered} Axis\text{ \lparen-8,0\rparen , \lparen8,0\rparen; Focus \lparen-10,0\rparen,\lparen-10,0\rparen} \\ \\ \end{gathered}[/tex]
The standard form of the equation of the hyperbola
[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex][tex]\begin{gathered} a=8 \\ c=10 \\ b^2=c^2-a^2 \\ b^2=10^2-8^2 \\ b^2=100-64 \\ b^2=36 \\ b=\sqrt{36} \\ b=6 \\ \\ \end{gathered}[/tex]
Now substitute into the standard form
[tex]\frac{x^2}{64}-\frac{y^2}{36}=1[/tex]
The final answer
Option B
