Given:
The equation is given as,
[tex]\begin{gathered} x\text{ - 5y = 10} \\ 6x\text{ - 3y + 9 = 0} \end{gathered}[/tex]
Required:
The equation of the in slope intercept form.
Explanation:
The slope-intercept form is given as,
[tex]y\text{ = mx + c}[/tex]
Where m is the slope and c is the intercept.
The slope-intercept form for the first equation is calculated as,
[tex]\begin{gathered} x\text{ - 5y = 10} \\ 5y\text{ = x - 10} \\ y\text{ = }\frac{x}{5}\text{ - }\frac{10}{5} \\ y\text{ = }\frac{x}{5}\text{ - 2} \end{gathered}[/tex]
The slope-intercept form for the second equation is calculated as,
[tex]\begin{gathered} 6x\text{ - 3y + 9 = 0} \\ 3y\text{ = 6x + 9} \\ y\text{ = }\frac{6x}{3}\text{ + }\frac{9}{3} \\ y\text{ = 2x + 3} \end{gathered}[/tex]
Answer:
Thus the required equation in slope intercept form is,
[tex]\begin{gathered} y\text{ = }\frac{x}{5}\text{ - 2} \\ y\text{ = 2x + 3} \end{gathered}[/tex]
The graph of the equation y = x/5 - 2 is given as,
The graph of the equation y = 2x + 3 is given as,
