The shape is a triangular pyramid.
The total surface area of the triangular pyramid is;
[tex]TSA=3(\frac{1}{2}\times9\times9.46)+\frac{1}{2}(9\sin 60^o\times9)[/tex][tex]\begin{gathered} TSA=3(42.57)+\frac{1}{2}(70.14) \\ TSA=162.78m^2 \end{gathered}[/tex]
Also, the volume of the triangular pyramid is;
[tex]\begin{gathered} V=\frac{1}{3}(\frac{1}{2}(9\sin 60^o\times9)\times9.1) \\ V=\frac{1}{3}(319.17) \\ V=106.39m^3 \end{gathered}[/tex]
